Optimal. Leaf size=146 \[ -\frac{3 i c^3 \sqrt{c-i c \tan (e+f x)}}{4 a^2 f (c+i c \tan (e+f x))}+\frac{i c^3 (c-i c \tan (e+f x))^{3/2}}{2 a^2 f (c+i c \tan (e+f x))^2}+\frac{3 i c^{5/2} \tanh ^{-1}\left (\frac{\sqrt{c-i c \tan (e+f x)}}{\sqrt{2} \sqrt{c}}\right )}{4 \sqrt{2} a^2 f} \]
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Rubi [A] time = 0.187667, antiderivative size = 146, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 5, integrand size = 33, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.152, Rules used = {3522, 3487, 47, 63, 206} \[ -\frac{3 i c^3 \sqrt{c-i c \tan (e+f x)}}{4 a^2 f (c+i c \tan (e+f x))}+\frac{i c^3 (c-i c \tan (e+f x))^{3/2}}{2 a^2 f (c+i c \tan (e+f x))^2}+\frac{3 i c^{5/2} \tanh ^{-1}\left (\frac{\sqrt{c-i c \tan (e+f x)}}{\sqrt{2} \sqrt{c}}\right )}{4 \sqrt{2} a^2 f} \]
Antiderivative was successfully verified.
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Rule 3522
Rule 3487
Rule 47
Rule 63
Rule 206
Rubi steps
\begin{align*} \int \frac{(c-i c \tan (e+f x))^{5/2}}{(a+i a \tan (e+f x))^2} \, dx &=\frac{\int \cos ^4(e+f x) (c-i c \tan (e+f x))^{9/2} \, dx}{a^2 c^2}\\ &=\frac{\left (i c^3\right ) \operatorname{Subst}\left (\int \frac{(c+x)^{3/2}}{(c-x)^3} \, dx,x,-i c \tan (e+f x)\right )}{a^2 f}\\ &=\frac{i c^3 (c-i c \tan (e+f x))^{3/2}}{2 a^2 f (c+i c \tan (e+f x))^2}-\frac{\left (3 i c^3\right ) \operatorname{Subst}\left (\int \frac{\sqrt{c+x}}{(c-x)^2} \, dx,x,-i c \tan (e+f x)\right )}{4 a^2 f}\\ &=\frac{i c^3 (c-i c \tan (e+f x))^{3/2}}{2 a^2 f (c+i c \tan (e+f x))^2}-\frac{3 i c^3 \sqrt{c-i c \tan (e+f x)}}{4 a^2 f (c+i c \tan (e+f x))}+\frac{\left (3 i c^3\right ) \operatorname{Subst}\left (\int \frac{1}{(c-x) \sqrt{c+x}} \, dx,x,-i c \tan (e+f x)\right )}{8 a^2 f}\\ &=\frac{i c^3 (c-i c \tan (e+f x))^{3/2}}{2 a^2 f (c+i c \tan (e+f x))^2}-\frac{3 i c^3 \sqrt{c-i c \tan (e+f x)}}{4 a^2 f (c+i c \tan (e+f x))}+\frac{\left (3 i c^3\right ) \operatorname{Subst}\left (\int \frac{1}{2 c-x^2} \, dx,x,\sqrt{c-i c \tan (e+f x)}\right )}{4 a^2 f}\\ &=\frac{3 i c^{5/2} \tanh ^{-1}\left (\frac{\sqrt{c-i c \tan (e+f x)}}{\sqrt{2} \sqrt{c}}\right )}{4 \sqrt{2} a^2 f}+\frac{i c^3 (c-i c \tan (e+f x))^{3/2}}{2 a^2 f (c+i c \tan (e+f x))^2}-\frac{3 i c^3 \sqrt{c-i c \tan (e+f x)}}{4 a^2 f (c+i c \tan (e+f x))}\\ \end{align*}
Mathematica [A] time = 2.63346, size = 138, normalized size = 0.95 \[ \frac{c^2 (\sin (2 (e+f x))+i \cos (2 (e+f x))) \left (3 \sqrt{2} \sqrt{c} (\cos (2 (e+f x))+i \sin (2 (e+f x))) \tanh ^{-1}\left (\frac{\sqrt{c-i c \tan (e+f x)}}{\sqrt{2} \sqrt{c}}\right )-\sqrt{c-i c \tan (e+f x)} (5 i \sin (2 (e+f x))+\cos (2 (e+f x))+1)\right )}{8 a^2 f} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.034, size = 96, normalized size = 0.7 \begin{align*}{\frac{-2\,i{c}^{3}}{f{a}^{2}} \left ({\frac{1}{ \left ( -c-ic\tan \left ( fx+e \right ) \right ) ^{2}} \left ( -{\frac{5}{8} \left ( c-ic\tan \left ( fx+e \right ) \right ) ^{{\frac{3}{2}}}}+{\frac{3\,c}{4}\sqrt{c-ic\tan \left ( fx+e \right ) }} \right ) }-{\frac{3\,\sqrt{2}}{16}{\it Artanh} \left ({\frac{\sqrt{2}}{2}\sqrt{c-ic\tan \left ( fx+e \right ) }{\frac{1}{\sqrt{c}}}} \right ){\frac{1}{\sqrt{c}}}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.51799, size = 783, normalized size = 5.36 \begin{align*} -\frac{{\left (3 \, \sqrt{\frac{1}{2}} a^{2} f \sqrt{-\frac{c^{5}}{a^{4} f^{2}}} e^{\left (4 i \, f x + 4 i \, e\right )} \log \left (-\frac{3 \,{\left (-i \, c^{3} + \sqrt{2} \sqrt{\frac{1}{2}}{\left (a^{2} f e^{\left (2 i \, f x + 2 i \, e\right )} + a^{2} f\right )} \sqrt{\frac{c}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}} \sqrt{-\frac{c^{5}}{a^{4} f^{2}}}\right )} e^{\left (-i \, f x - i \, e\right )}}{2 \, a^{2} f}\right ) - 3 \, \sqrt{\frac{1}{2}} a^{2} f \sqrt{-\frac{c^{5}}{a^{4} f^{2}}} e^{\left (4 i \, f x + 4 i \, e\right )} \log \left (-\frac{3 \,{\left (-i \, c^{3} - \sqrt{2} \sqrt{\frac{1}{2}}{\left (a^{2} f e^{\left (2 i \, f x + 2 i \, e\right )} + a^{2} f\right )} \sqrt{\frac{c}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}} \sqrt{-\frac{c^{5}}{a^{4} f^{2}}}\right )} e^{\left (-i \, f x - i \, e\right )}}{2 \, a^{2} f}\right ) - \sqrt{2}{\left (-3 i \, c^{2} e^{\left (4 i \, f x + 4 i \, e\right )} - i \, c^{2} e^{\left (2 i \, f x + 2 i \, e\right )} + 2 i \, c^{2}\right )} \sqrt{\frac{c}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}}\right )} e^{\left (-4 i \, f x - 4 i \, e\right )}}{8 \, a^{2} f} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: AttributeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (-i \, c \tan \left (f x + e\right ) + c\right )}^{\frac{5}{2}}}{{\left (i \, a \tan \left (f x + e\right ) + a\right )}^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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